Termination w.r.t. Q of the following Term Rewriting System could not be shown:
Q restricted rewrite system:
The TRS R consists of the following rules:
h1(f1(f1(x))) -> h1(f1(g1(f1(x))))
f1(g1(f1(x))) -> f1(f1(x))
Q is empty.
↳ QTRS
↳ DependencyPairsProof
Q restricted rewrite system:
The TRS R consists of the following rules:
h1(f1(f1(x))) -> h1(f1(g1(f1(x))))
f1(g1(f1(x))) -> f1(f1(x))
Q is empty.
Q DP problem:
The TRS P consists of the following rules:
H1(f1(f1(x))) -> H1(f1(g1(f1(x))))
H1(f1(f1(x))) -> F1(g1(f1(x)))
F1(g1(f1(x))) -> F1(f1(x))
The TRS R consists of the following rules:
h1(f1(f1(x))) -> h1(f1(g1(f1(x))))
f1(g1(f1(x))) -> f1(f1(x))
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ DependencyGraphProof
Q DP problem:
The TRS P consists of the following rules:
H1(f1(f1(x))) -> H1(f1(g1(f1(x))))
H1(f1(f1(x))) -> F1(g1(f1(x)))
F1(g1(f1(x))) -> F1(f1(x))
The TRS R consists of the following rules:
h1(f1(f1(x))) -> h1(f1(g1(f1(x))))
f1(g1(f1(x))) -> f1(f1(x))
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
The approximation of the Dependency Graph contains 1 SCC with 2 less nodes.
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ DependencyGraphProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
H1(f1(f1(x))) -> H1(f1(g1(f1(x))))
The TRS R consists of the following rules:
h1(f1(f1(x))) -> h1(f1(g1(f1(x))))
f1(g1(f1(x))) -> f1(f1(x))
Q is empty.
We have to consider all minimal (P,Q,R)-chains.